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* Facebook -> Meta in copyright rg --files | xargs sed -i 's#Copyright (c) Facebook, Inc. and its affiliates.#Copyright (c) Meta Platforms, Inc. and affiliates.#g' * Manual tweaks
169 lines
6.0 KiB
JavaScript
169 lines
6.0 KiB
JavaScript
/**
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* Copyright (c) Meta Platforms, Inc. and affiliates.
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*
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* This source code is licensed under the MIT license found in the
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* LICENSE file in the root directory of this source tree.
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*
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* @flow
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*/
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// Ids are base 32 strings whose binary representation corresponds to the
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// position of a node in a tree.
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// Every time the tree forks into multiple children, we add additional bits to
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// the left of the sequence that represent the position of the child within the
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// current level of children.
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//
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// 00101 00010001011010101
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// ╰─┬─╯ ╰───────┬───────╯
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// Fork 5 of 20 Parent id
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//
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// The leading 0s are important. In the above example, you only need 3 bits to
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// represent slot 5. However, you need 5 bits to represent all the forks at
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// the current level, so we must account for the empty bits at the end.
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//
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// For this same reason, slots are 1-indexed instead of 0-indexed. Otherwise,
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// the zeroth id at a level would be indistinguishable from its parent.
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//
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// If a node has only one child, and does not materialize an id (i.e. does not
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// contain a useId hook), then we don't need to allocate any space in the
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// sequence. It's treated as a transparent indirection. For example, these two
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// trees produce the same ids:
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//
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// <> <>
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// <Indirection> <A />
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// <A /> <B />
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// </Indirection> </>
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// <B />
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// </>
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//
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// However, we cannot skip any node that materializes an id. Otherwise, a parent
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// id that does not fork would be indistinguishable from its child id. For
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// example, this tree does not fork, but the parent and child must have
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// different ids.
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//
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// <Parent>
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// <Child />
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// </Parent>
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//
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// To handle this scenario, every time we materialize an id, we allocate a
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// new level with a single slot. You can think of this as a fork with only one
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// prong, or an array of children with length 1.
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//
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// It's possible for the size of the sequence to exceed 32 bits, the max
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// size for bitwise operations. When this happens, we make more room by
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// converting the right part of the id to a string and storing it in an overflow
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// variable. We use a base 32 string representation, because 32 is the largest
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// power of 2 that is supported by toString(). We want the base to be large so
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// that the resulting ids are compact, and we want the base to be a power of 2
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// because every log2(base) bits corresponds to a single character, i.e. every
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// log2(32) = 5 bits. That means we can lop bits off the end 5 at a time without
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// affecting the final result.
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export type TreeContext = {
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+id: number,
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+overflow: string,
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};
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export const emptyTreeContext = {
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id: 1,
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overflow: '',
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};
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export function getTreeId(context: TreeContext): string {
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const overflow = context.overflow;
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const idWithLeadingBit = context.id;
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const id = idWithLeadingBit & ~getLeadingBit(idWithLeadingBit);
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return id.toString(32) + overflow;
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}
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export function pushTreeContext(
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baseContext: TreeContext,
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totalChildren: number,
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index: number,
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): TreeContext {
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const baseIdWithLeadingBit = baseContext.id;
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const baseOverflow = baseContext.overflow;
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// The leftmost 1 marks the end of the sequence, non-inclusive. It's not part
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// of the id; we use it to account for leading 0s.
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const baseLength = getBitLength(baseIdWithLeadingBit) - 1;
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const baseId = baseIdWithLeadingBit & ~(1 << baseLength);
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const slot = index + 1;
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const length = getBitLength(totalChildren) + baseLength;
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// 30 is the max length we can store without overflowing, taking into
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// consideration the leading 1 we use to mark the end of the sequence.
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if (length > 30) {
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// We overflowed the bitwise-safe range. Fall back to slower algorithm.
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// This branch assumes the length of the base id is greater than 5; it won't
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// work for smaller ids, because you need 5 bits per character.
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//
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// We encode the id in multiple steps: first the base id, then the
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// remaining digits.
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//
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// Each 5 bit sequence corresponds to a single base 32 character. So for
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// example, if the current id is 23 bits long, we can convert 20 of those
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// bits into a string of 4 characters, with 3 bits left over.
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//
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// First calculate how many bits in the base id represent a complete
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// sequence of characters.
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const numberOfOverflowBits = baseLength - (baseLength % 5);
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// Then create a bitmask that selects only those bits.
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const newOverflowBits = (1 << numberOfOverflowBits) - 1;
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// Select the bits, and convert them to a base 32 string.
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const newOverflow = (baseId & newOverflowBits).toString(32);
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// Now we can remove those bits from the base id.
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const restOfBaseId = baseId >> numberOfOverflowBits;
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const restOfBaseLength = baseLength - numberOfOverflowBits;
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// Finally, encode the rest of the bits using the normal algorithm. Because
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// we made more room, this time it won't overflow.
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const restOfLength = getBitLength(totalChildren) + restOfBaseLength;
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const restOfNewBits = slot << restOfBaseLength;
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const id = restOfNewBits | restOfBaseId;
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const overflow = newOverflow + baseOverflow;
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return {
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id: (1 << restOfLength) | id,
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overflow,
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};
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} else {
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// Normal path
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const newBits = slot << baseLength;
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const id = newBits | baseId;
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const overflow = baseOverflow;
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return {
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id: (1 << length) | id,
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overflow,
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};
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}
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}
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function getBitLength(number: number): number {
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return 32 - clz32(number);
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}
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function getLeadingBit(id: number) {
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return 1 << (getBitLength(id) - 1);
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}
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// TODO: Math.clz32 is supported in Node 12+. Maybe we can drop the fallback.
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const clz32 = Math.clz32 ? Math.clz32 : clz32Fallback;
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// Count leading zeros.
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// Based on:
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// https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Math/clz32
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const log = Math.log;
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const LN2 = Math.LN2;
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function clz32Fallback(x: number): number {
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const asUint = x >>> 0;
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if (asUint === 0) {
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return 32;
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}
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return (31 - ((log(asUint) / LN2) | 0)) | 0;
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}
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